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Area of Circle Formula and Every Other Area Formula You Need

12 formulasCalculatorUpdated 22 Oct 2026

The area of circle formula is A=πr2A = \pi r^2, where rr is the radius; if you know the diameter dd instead, use A=πd24A = \dfrac{\pi d^2}{4}. With π=227\pi = \tfrac{22}{7}, a circle of radius 7 cm covers 154 square centimetres.

This page starts with the circle, shows why the answer is pi r squared, and then walks through every flat shape that comes up in school mensuration: triangles, squares, rectangles, parallelograms, rhombuses, trapeziums, general quadrilaterals, ellipses, sectors and semicircles. Each shape gets its formula, what the letters stand for and a short solved example. Type your own numbers into the area calculator below to see the same steps for any shape.

Area of circle formula

Key formulas

  • Area of a circle (radius)

    A=πr2A = \pi r^2
  • Area of a circle (diameter)

    A=πd24A = \dfrac{\pi d^2}{4}

    d = 2r

  • Area of a triangle

    A=12×b×hA = \dfrac{1}{2} \times b \times h

    b is the base, h the perpendicular height

  • Triangle with 3 sides (Heron)

    A=s(s−a)(s−b)(s−c),  s=a+b+c2A = \sqrt{s(s-a)(s-b)(s-c)},\; s = \dfrac{a+b+c}{2}
  • Equilateral triangle

    A=34a2A = \dfrac{\sqrt{3}}{4}a^2
  • Square and rectangle

    Asquare=a2,Arect=l×bA_{\text{square}} = a^2, \quad A_{\text{rect}} = l \times b
  • Parallelogram

    A=b×hA = b \times h
  • Rhombus

    A=12d1d2A = \dfrac{1}{2} d_1 d_2

    d1 and d2 are the diagonals

  • Trapezium (trapezoid)

    A=12(a+b) hA = \dfrac{1}{2}(a+b)\,h

    a and b are the parallel sides, h the distance between them

  • Ellipse

    A=πabA = \pi a b

    a and b are the semi-axes

  • Sector of angle theta

    A=θ360∘×πr2A = \dfrac{\theta}{360^\circ} \times \pi r^2

    θ in degrees

  • Semicircle

    A=12πr2A = \dfrac{1}{2}\pi r^2

Area of circle formula with radius and diameter

A circle is fixed by one length, its radius rr: the distance from the centre to any point on the edge. The diameter dd runs right across through the centre, so d=2rd = 2r. The space enclosed by the boundary is the area, and it is measured in square units such as cm2\mathrm{cm^2} or m2\mathrm{m^2}.

When the radius is given, square it and multiply by pi:

A=πr2A = \pi r^2

When only the diameter is given, you can halve it first, or put r=d2r = \tfrac{d}{2} straight into the formula:

A=π(d2)2=πd24A = \pi \left(\dfrac{d}{2}\right)^2 = \dfrac{\pi d^2}{4}

Textbook questions usually tell you which value of π\pi to use: 227\tfrac{22}{7} (handy when the radius is a multiple of 7) or 3.14. Follow whatever value the question names. If it says nothing, leave the answer in terms of π\pi or use 3.14.

Example 1: radius given

Find the area of a circular plate of radius 7 cm. Take π=227\pi = \tfrac{22}{7}.

A=227×7×7=22×7=154A = \dfrac{22}{7} \times 7 \times 7 = 22 \times 7 = 154

Answer: 154 cm2154\ \mathrm{cm^2}.

Example 2: diameter given

A round table top has a diameter of 10 cm on a scale drawing. Take π=3.14\pi = 3.14.

A=3.14×1024=3144=78.5A = \dfrac{3.14 \times 10^2}{4} = \dfrac{314}{4} = 78.5

Answer: 78.5 cm278.5\ \mathrm{cm^2}.

Common slip: students often square the diameter and forget to divide by 4, which makes the answer four times too big. Another slip is writing the unit as cm instead of square cm.

Why the area of a circle is pi r squared

Here is the cutting proof that most teachers draw on the board. It is the simplest way to derive the formula of area of circle without calculus.

  1. Cut the circle into many equal sectors, like slices of a pizza, say 16 or 32 of them.
  2. Lay the slices in a row, point up, point down, point up, and so on.
  3. The shape now looks like a wavy parallelogram. As you cut thinner slices, the wavy edges flatten and the shape becomes a rectangle.
  4. The height of that rectangle is the radius rr. Its length is half the circumference, because half the curved edges lie along the top and half along the bottom: 12×2πr=πr\tfrac{1}{2} \times 2\pi r = \pi r.
A=length×height=πr×r=πr2A = \text{length} \times \text{height} = \pi r \times r = \pi r^2

In class 12 you can also prove it by integration: adding thin rings of radius xx and width dxdx gives ∫0r2πx dx=πr2\int_0^r 2\pi x\,dx = \pi r^2. The integration formulas page covers that tool. The link between area and the boundary length of a circle is on the perimeter and circumference page.

Triangle area formula: base, height, three sides and equilateral

The basic area of triangle formula is half of base times height:

A=12×b×hA = \dfrac{1}{2} \times b \times h

The height must be perpendicular to the base you chose. In a right triangle the two legs are already perpendicular, so one leg is the base and the other is the height. In an obtuse triangle the height may fall outside the triangle, and that is fine.

Example 3: base and height

A triangular flag has a base of 12 cm and a height of 9 cm.

A=12×12×9=54A = \dfrac{1}{2} \times 12 \times 9 = 54

Answer: 54 cm254\ \mathrm{cm^2}.

Area of triangle with 3 sides formula

When no height is given but all three sides are, use Heron's formula (class 9). For sides 13, 14 and 15 cm, s=21s = 21, so

A=21×8×7×6=7056=84 cm2A = \sqrt{21 \times 8 \times 7 \times 6} = \sqrt{7056} = 84\ \mathrm{cm^2}

The proof and more examples are on the Heron's formula page.

Area of equilateral triangle formula

All sides are equal to aa, and the height works out to 32a\tfrac{\sqrt{3}}{2}a, so A=34a2A = \tfrac{\sqrt{3}}{4}a^2. For a side of 6 cm, A=93≈15.59 cm2A = 9\sqrt{3} \approx 15.59\ \mathrm{cm^2}.

Isosceles triangle area formula

If the two equal sides are aa and the base is bb, the height splits the base in half, and Pythagoras gives the height. The result is

A=b44a2−b2A = \dfrac{b}{4}\sqrt{4a^2 - b^2}

With a=10a = 10 and b=12b = 12: the height is 8, and the area is 124×256=3×16=48\tfrac{12}{4} \times \sqrt{256} = 3 \times 16 = 48 square units.

Square, rectangle and parallelogram area formulas

Area of square formula

A square with side aa has area a2a^2. If you only know its diagonal dd, the area is d22\tfrac{d^2}{2}, because the two diagonals of a square are equal and meet at right angles. A square of side 9 m covers 81 square metres; one with a diagonal of 10 cm covers 50 square centimetres. People sometimes search "area of square ka formula": it is the same, side into side.

Area of rectangle formula

Length times breadth: A=l×bA = l \times b. A classroom floor 15 m long and 8 m wide has an area of 120 square metres. Both lengths must be in the same unit before you multiply.

Parallelogram area formula

Base times the perpendicular height, A=b×hA = b \times h. Do not multiply the two slanting sides together: that gives a wrong, larger number. A parallelogram with base 11 cm and height 6 cm has area 66 square centimetres. Cut a triangle off one end and slide it to the other end, and you get a rectangle of the same base and height, which is why the formula matches the rectangle one.

Rhombus, trapezium and quadrilateral area formulas

Area of rhombus formula

The diagonals of a rhombus cut each other at right angles, so the area is half their product, 12d1d2\tfrac{1}{2}d_1 d_2. A rhombus is also a parallelogram, so base times height works too.

Example 4: rhombus from diagonals

The diagonals of a rhombus are 16 cm and 12 cm. Find its area and its side.

Area: 12×16×12=96\tfrac{1}{2} \times 16 \times 12 = 96.

The half diagonals are 8 and 6, and they meet at a right angle, so the side is 82+62=10\sqrt{8^2 + 6^2} = 10.

Answer: area 96 cm296\ \mathrm{cm^2}, side 10 cm.

Area of trapezium formula

A trapezium (called a trapezoid in American books) has one pair of parallel sides, aa and bb. Add them, halve the sum, and multiply by the distance hh between them: A=12(a+b)hA = \tfrac{1}{2}(a+b)h. This trapezoid area formula is part of middle school mensuration.

Example 5: trapezium-shaped field

The parallel sides of a field are 9 m and 15 m, and they are 7 m apart.

A=12(9+15)×7=12×7=84A = \dfrac{1}{2}(9 + 15) \times 7 = 12 \times 7 = 84

Answer: 84 m284\ \mathrm{m^2}.

Area of a general quadrilateral

Draw one diagonal dd and drop perpendiculars h1h_1 and h2h_2 on it from the other two corners. The diagonal splits the shape into two triangles, so A=12d(h1+h2)A = \tfrac{1}{2}d(h_1 + h_2). With d=18d = 18, h1=5h_1 = 5 and h2=7h_2 = 7, the area is 108 square units. If only the four sides and one diagonal are known, find each triangle by Heron's formula and add.

Ellipse, sector, semicircle and segment

Area of an ellipse

An ellipse is a stretched circle with a semi-major axis aa and a semi-minor axis bb. Its area is πab\pi ab. When a=b=ra = b = r, this turns back into πr2\pi r^2. For a=5a = 5 and b=3b = 3, the area is 15π≈47.1215\pi \approx 47.12 square units.

Area of sector formula

A sector is the slice between two radii. Its share of the full circle equals its angle θ\theta out of 360 degrees:

A=θ360∘×πr2A = \dfrac{\theta}{360^\circ} \times \pi r^2

Example 6: sector of 60 degrees

Find the area of a sector of radius 21 cm and angle 60 degrees.

A=60360×227×21×21=16×1386=231A = \dfrac{60}{360} \times \dfrac{22}{7} \times 21 \times 21 = \dfrac{1}{6} \times 1386 = 231

Answer: 231 cm2231\ \mathrm{cm^2}.

Semicircle and quadrant

A semicircle is a sector of 180 degrees, so its area is 12πr2\tfrac{1}{2}\pi r^2; radius 7 cm gives 77 square cm with π=227\pi = \tfrac{22}{7}. A quadrant (90 degrees) is a quarter of the circle.

Area of segment formula

A minor segment is the part between a chord and its arc. Take the sector and remove the triangle formed by the two radii and the chord:

Asegment=θ360∘πr2−12r2sin⁡θA_{\text{segment}} = \dfrac{\theta}{360^\circ}\pi r^2 - \dfrac{1}{2}r^2 \sin\theta

For r=14r = 14 cm and θ=90∘\theta = 90^\circ, with π=227\pi = \tfrac{22}{7}: the sector is 154, the right triangle is 12×14×14=98\tfrac{1}{2} \times 14 \times 14 = 98, so the segment is 56 square cm. Sectors and segments form the class 10 chapter Areas Related to Circles. For values like sin⁡60∘\sin 60^\circ, see the trigonometry formulas page.

Ring (annulus)

The region between two circles with the same centre has area π(R2−r2)\pi(R^2 - r^2). For outer radius 14 and inner radius 7, with π=227\pi = \tfrac{22}{7}, that is 227×147=462\tfrac{22}{7} \times 147 = 462 square units.

Mensuration formula summary table

Here are the mensuration formulas for plane figures in one table. Copy it into your notebook, or save the one-page PDF version offered below.

ShapeAreaLetters
Circleπr2\pi r^2 or πd24\tfrac{\pi d^2}{4}r radius, d diameter
Triangle12bh\tfrac{1}{2}bhb base, h height
Triangle, three sidess(s−a)(s−b)(s−c)\sqrt{s(s-a)(s-b)(s-c)}s half the perimeter
Equilateral triangle34a2\tfrac{\sqrt{3}}{4}a^2a side
Squarea2a^2 or d22\tfrac{d^2}{2}a side, d diagonal
Rectanglelblbl length, b breadth
Parallelogrambhbhb base, h height
Rhombus12d1d2\tfrac{1}{2}d_1d_2diagonals
Trapezium12(a+b)h\tfrac{1}{2}(a+b)ha, b parallel sides
Regular hexagon332a2\tfrac{3\sqrt{3}}{2}a^2a side
Ellipseπab\pi absemi-axes
Sectorθ360∘πr2\tfrac{\theta}{360^\circ}\pi r^2angle in degrees

The hexagon area formula comes from six equilateral triangles of side aa; a side of 4 cm gives 243≈41.5724\sqrt{3} \approx 41.57 square cm. Solid shapes need a different set of formulas. The area of cylinder, cuboid and sphere surfaces (curved and total surface area) is covered with the volume and surface area formulas, where, for example, the sphere has surface area 4πr24\pi r^2.

Units of area and conversions

Area is always in square units. When a length unit changes by a factor, the area unit changes by the square of that factor. That is the root of most conversion mistakes.

  • 1 cm2=100 mm21\ \mathrm{cm^2} = 100\ \mathrm{mm^2} (since 1 cm = 10 mm)
  • 1 m2=10 000 cm21\ \mathrm{m^2} = 10\,000\ \mathrm{cm^2} (since 1 m = 100 cm)
  • 1 hectare =10 000 m2= 10\,000\ \mathrm{m^2}, and 1 are =100 m2= 100\ \mathrm{m^2}
  • 1 km2=1001\ \mathrm{km^2} = 100 hectares =106 m2= 10^6\ \mathrm{m^2}

So a floor of 120 square metres is 1 200 000 square centimetres, not 12 000. Convert lengths first and then multiply. That is safer than converting the final area. Percentage questions on area, such as "each side grows by 10 percent, by what percent does the area grow?", use the successive change idea on the percentage formula page. Here the area grows by 21 percent, not 20, because 1.12=1.211.1^2 = 1.21.

Mensuration formula in Hindi

Hindi medium students meet the same formulas with these names. Mensuration itself is क्षेत्रमिति, and area is क्षेत्रफल.

EnglishHindi
Area of circleवृत्त का क्षेत्रफल = πr²
Radius, diameterत्रिज्या, व्यास
Area of triangleत्रिभुज का क्षेत्रफल = ½ × आधार × ऊँचाई
Area of rectangleआयत का क्षेत्रफल = लंबाई × चौड़ाई
Area of squareवर्ग का क्षेत्रफल = भुजा × भुजा
Parallelogram, rhombusसमांतर चतुर्भुज, समचतुर्भुज
Trapeziumसमलंब चतुर्भुज
Diagonal, sectorविकर्ण, त्रिज्यखंड

Which class teaches which area formula

Knowing where a formula sits in the syllabus helps you revise the right chapter. The rectangle, square, triangle, parallelogram and circle come first, in the middle school classes, followed by the trapezium, rhombus and general quadrilateral. Class 9 teaches Heron's formula for a triangle with three sides. Class 10 has the chapter on areas related to circles, which covers sectors and segments, plus a separate chapter on solids. The exact class for each middle school shape depends on your book edition, so check its contents page.

Competitive exams such as the ones after class 12 mix these shapes: a square with a circle cut out, a rectangle with semicircles on two ends, or a path around a garden. The rule is always the same: break the figure into standard shapes, find each area, then add or subtract. For the full list across topics, see all maths formulas.

Download the PDF

Questions students ask

What is the area of circle formula?

The area of a circle is πr2\pi r^2, where rr is the radius. With the diameter it is πd24\tfrac{\pi d^2}{4}. Use π=227\pi = \tfrac{22}{7} or 3.14 as your book says.

How do I find the area of a circle from its circumference?

First get the radius from C=2πrC = 2\pi r, so r=C2πr = \tfrac{C}{2\pi}, then square it and multiply by π\pi. In one step, A=C24πA = \tfrac{C^2}{4\pi}. With π=227\pi = \tfrac{22}{7}, a circumference of 88 cm gives a radius of 14 cm and an area of 616 square cm.

What is the formula of area of triangle when the height is not given?

Use Heron's formula with the three sides: s(s−a)(s−b)(s−c)\sqrt{s(s-a)(s-b)(s-c)}, where ss is half the perimeter. If two sides and the angle between them are known, use 12absin⁡C\tfrac{1}{2}ab\sin C.

Is a trapezium the same as a trapezoid?

Yes for school purposes. Indian and British books say trapezium, American books say trapezoid, and both mean a quadrilateral with one pair of parallel sides. The area is 12(a+b)h\tfrac{1}{2}(a+b)h in either name.

What is the difference between area and perimeter?

Area measures the surface inside a shape and is in square units. Perimeter is the length of the boundary and is in plain length units. A 4 by 4 square and a 2 by 8 rectangle have the same area, 16, but perimeters of 16 and 20.

Why do we use 22 by 7 for pi?

Pi is irrational, so any fraction is an approximation. 227≈3.1429\tfrac{22}{7} \approx 3.1429 is close to the true value 3.14159 and cancels nicely when the radius is a multiple of 7, which keeps hand working short.

What is the area of sector formula in radians?

If the angle θ\theta is in radians, the sector area is 12r2θ\tfrac{1}{2}r^2\theta. This is the same as the degree version, because a full turn of 360 degrees equals 2π2\pi radians.