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Volume Formula and Surface Area of Every Solid

10 formulasCalculatorUpdated 22 Oct 2026

The volume formula for most solids comes from one idea: volume equals base area times height for straight solids like the cube, cuboid, cylinder and prism (V=BhV = Bh), and one third of that for pointed solids like the cone and pyramid (V=13BhV = \tfrac{1}{3}Bh). The sphere, V=43πr3V = \tfrac{4}{3}\pi r^3, is the one you simply have to remember.

On this page you will find the volume, total surface area (TSA) and curved or lateral surface area (CSA, LSA) of nine solids, how cubic units convert to litres, and solved problems on combined solids and melting and recasting. The volume calculator below shows the substituted steps for the common shapes, so use it to test your own answers.

Volume formula

Key formulas

  • Cube (side a)

    V=a3,  TSA=6a2,  LSA=4a2V = a^3,\; \text{TSA} = 6a^2,\; \text{LSA} = 4a^2
  • Cuboid

    V=lbh,  TSA=2(lb+bh+hl)V = lbh,\; \text{TSA} = 2(lb + bh + hl)
  • Cylinder

    V=πr2h,  CSA=2πrh,  TSA=2πr(r+h)V = \pi r^2 h,\; \text{CSA} = 2\pi r h,\; \text{TSA} = 2\pi r(r + h)

    r is the base radius, h the height

  • Cone

    V=13πr2h,  CSA=πrlV = \tfrac{1}{3}\pi r^2 h,\; \text{CSA} = \pi r l

    slant height l = √(r² + h²)

  • Sphere

    V=43πr3,  S=4πr2V = \tfrac{4}{3}\pi r^3,\; S = 4\pi r^2
  • Hemisphere

    V=23πr3,  CSA=2πr2,  TSA=3πr2V = \tfrac{2}{3}\pi r^3,\; \text{CSA} = 2\pi r^2,\; \text{TSA} = 3\pi r^2
  • Pyramid

    V=13×base area×hV = \tfrac{1}{3} \times \text{base area} \times h
  • Prism

    V=base area×h,  LSA=base perimeter×hV = \text{base area} \times h,\; \text{LSA} = \text{base perimeter} \times h
  • Frustum of a cone

    V=13πh(R2+r2+Rr)V = \tfrac{1}{3}\pi h(R^2 + r^2 + Rr)

    R and r are the radii of the two ends, h the height

  • Litres

    1 L=1000 cm31\ \mathrm{L} = 1000\ \mathrm{cm^3}, 1 m3=1000 L1\ \mathrm{m^3} = 1000\ \mathrm{L}

What volume means in maths and physics

Here is the volume definition in plain words: volume is the amount of space a solid takes up. Think of how many unit cubes, each 1 cm on every edge, you could pack inside it. That is why volume is counted in cubic units: cm3\mathrm{cm^3}, m3\mathrm{m^3}. The SI unit used in physics is the cubic metre, and for liquids we use litres and millilitres.

Surface area is different: it is the total area of the outer faces, measured in square units, and tells you how much paint, paper or sheet metal you need. Questions say "total surface area" when every face counts, and "curved" or "lateral" surface area when the top and bottom are left out (an open pipe, the walls of a room).

In physics, the volume of an irregular stone is found by dropping it in a measuring cylinder and reading the rise in water level. Density is mass divided by volume, so the same formulas appear in science numericals too.

Volume of cube formula and cuboid formula

Cube

Every edge of a cube is the same length aa, so the volume is side times side times side, a3a^3 (some notes write it as s x s x s). The six faces are squares, so TSA is 6a26a^2; leave out the top and bottom and the four walls give 4a24a^2. The long diagonal from one corner to the opposite one is 3 a\sqrt{3}\,a.

Example 1: a cube of side 5 cm

V=53=125,TSA=6×25=150,LSA=4×25=100V = 5^3 = 125,\quad \text{TSA} = 6 \times 25 = 150,\quad \text{LSA} = 4 \times 25 = 100

Answer: 125 cm3125\ \mathrm{cm^3}, TSA 150 cm2150\ \mathrm{cm^2}, LSA 100 cm2100\ \mathrm{cm^2}.

Cuboid (rectangular box)

A cuboid, or rectangular prism, has length ll, breadth bb and height hh. Its volume is lbhlbh. The surface area of a rectangular box has three pairs of equal faces, giving 2(lb+bh+hl)2(lb + bh + hl). The lateral surface area of a cuboid means the four side walls only: 2h(l+b)2h(l + b). That is the area you plaster when you paint the walls of a room but not the floor and ceiling.

Example 2: a box 10 cm by 6 cm by 4 cm

V=10×6×4=240V = 10 \times 6 \times 4 = 240.

TSA=2(60+24+40)=248\text{TSA} = 2(60 + 24 + 40) = 248.

LSA=2×4×(10+6)=128\text{LSA} = 2 \times 4 \times (10 + 6) = 128.

Answer: 240 cm3240\ \mathrm{cm^3}, 248 cm2248\ \mathrm{cm^2}, 128 cm2128\ \mathrm{cm^2}.

There is no "volume of a square": a square is flat and has only area. If a question says that, it means a cube.

Volume of cylinder formula and surface area

A cylinder is a circle pushed straight up through a height hh. Its base area is πr2\pi r^2, so V=πr2hV = \pi r^2 h. Unroll the curved side and you get a rectangle whose width is the base circumference 2πr2\pi r and whose height is hh: that is the CSA, 2πrh2\pi rh. Add two circular ends for the TSA, 2πr(r+h)2\pi r(r + h).

Example 3: radius 7 cm, height 10 cm

Take π=227\pi = \tfrac{22}{7} here and in the examples below unless stated otherwise.

V=227×7×7×10=1540V = \tfrac{22}{7} \times 7 \times 7 \times 10 = 1540.

CSA=2×227×7×10=440\text{CSA} = 2 \times \tfrac{22}{7} \times 7 \times 10 = 440.

TSA=2×227×7×(7+10)=748\text{TSA} = 2 \times \tfrac{22}{7} \times 7 \times (7 + 10) = 748.

Answer: 1540 cm31540\ \mathrm{cm^3}, CSA 440 cm2440\ \mathrm{cm^2}, TSA 748 cm2748\ \mathrm{cm^2}.

A hollow pipe with outer radius RR and inner radius rr holds metal of volume π(R2−r2)h\pi(R^2 - r^2)h.

Volume of cone formula and slant height

A cone with the same base and height as a cylinder holds exactly one third as much. You can test this with water: three full cones fill the cylinder. So V=13πr2hV = \tfrac{1}{3}\pi r^2 h.

The curved surface uses the slant height ll, not the vertical height. The radius, the height and the slant height form a right triangle, so l=r2+h2l = \sqrt{r^2 + h^2}. Then CSA is πrl\pi rl and TSA is πr(l+r)\pi r(l + r).

Example 4: radius 7 cm, height 24 cm

Slant height l=49+576=625=25l = \sqrt{49 + 576} = \sqrt{625} = 25.

V=13×227×49×24=1232V = \tfrac{1}{3} \times \tfrac{22}{7} \times 49 \times 24 = 1232.

CSA=227×7×25=550\text{CSA} = \tfrac{22}{7} \times 7 \times 25 = 550, and TSA=22×(25+7)=704\text{TSA} = 22 \times (25 + 7) = 704.

Answer: 1232 cm31232\ \mathrm{cm^3}, CSA 550 cm2550\ \mathrm{cm^2}, TSA 704 cm2704\ \mathrm{cm^2}.

Watch out: using hh in place of ll in πrl\pi rl is the single most common error in this chapter. Draw the right triangle every time.

Sphere volume formula and hemisphere

A sphere of radius rr has volume 43πr3\tfrac{4}{3}\pi r^3 and surface area 4πr24\pi r^2, which is four times the area of its biggest circle. Both formulas come from calculus or from Archimedes' comparison with a cylinder, and you are expected to memorise them in class 9.

A hemisphere is half a sphere. Its volume is 23πr3\tfrac{2}{3}\pi r^3 and its curved surface is 2πr22\pi r^2. A solid hemisphere also has a flat circular face, so its TSA is 2πr2+πr2=3πr22\pi r^2 + \pi r^2 = 3\pi r^2. A hollow bowl has only the curved part.

Example 5: sphere of radius 21 cm and hemisphere of radius 7 cm

Sphere: V=43×227×213=38 808V = \tfrac{4}{3} \times \tfrac{22}{7} \times 21^3 = 38\,808 and S=4×227×441=5544S = 4 \times \tfrac{22}{7} \times 441 = 5544.

Hemisphere: V=23×227×343≈718.67V = \tfrac{2}{3} \times \tfrac{22}{7} \times 343 \approx 718.67, CSA =308= 308, TSA =462= 462.

Answer: sphere 38 808 cm338\,808\ \mathrm{cm^3} and 5544 cm25544\ \mathrm{cm^2}; hemisphere about 718.67 cm3718.67\ \mathrm{cm^3}, CSA 308 cm2308\ \mathrm{cm^2}, TSA 462 cm2462\ \mathrm{cm^2}.

Note that a circle is flat, so it has no volume. A "volume of the circle formula" search usually means the sphere.

Pyramid volume formula, prism and frustum

Pyramid

Any pyramid, whatever the shape of its base, has V=13×base area×hV = \tfrac{1}{3} \times \text{base area} \times h. For a square base of side aa, that is 13a2h\tfrac{1}{3}a^2 h. The lateral surface is made of triangles; each has the base edge as its base and the slant height of the face as its height.

Example 6: square pyramid, base 6 m, height 4 m

V=13×36×4=48V = \tfrac{1}{3} \times 36 \times 4 = 48.

Slant height of a face =42+32=5= \sqrt{4^2 + 3^2} = 5 (3 is half the base edge).

LSA =4×12×6×5=60= 4 \times \tfrac{1}{2} \times 6 \times 5 = 60; TSA =60+36=96= 60 + 36 = 96.

Answer: 48 m348\ \mathrm{m^3}, LSA 60 m260\ \mathrm{m^2}, TSA 96 m296\ \mathrm{m^2}.

Prism

A prism keeps the same cross-section all along its length. Its volume is that cross-section area times the length. The lateral surface of a prism is a set of rectangles, one per edge of the base, so LSA == base perimeter ×h\times h, and TSA adds the two end faces. A triangular prism with a right triangle base of legs 3 cm and 4 cm (hypotenuse 5 cm) and length 10 cm has volume 6×10=60 cm36 \times 10 = 60\ \mathrm{cm^3}, LSA 12×10=120 cm212 \times 10 = 120\ \mathrm{cm^2} and TSA 132 cm2132\ \mathrm{cm^2}.

Frustum of a cone

Slice the top off a cone parallel to the base, and the bucket-shaped piece left is a frustum. With end radii RR and rr, height hh and slant height l=h2+(R−r)2l = \sqrt{h^2 + (R - r)^2}:

V=πh3(R2+r2+Rr),CSA=πl(R+r)V = \dfrac{\pi h}{3}(R^2 + r^2 + Rr), \quad \text{CSA} = \pi l(R + r)

For R=10R = 10, r=4r = 4, h=8h = 8 (cm): l=10l = 10, V=416π≈1306.24 cm3V = 416\pi \approx 1306.24\ \mathrm{cm^3} with π=3.14\pi = 3.14, CSA =140π≈439.6 cm2= 140\pi \approx 439.6\ \mathrm{cm^2}, and TSA, adding both circles, =256π≈803.84 cm2= 256\pi \approx 803.84\ \mathrm{cm^2}. The frustum is not in every board's current syllabus, so check yours; entrance tests still ask it.

Units, litres and capacity

Since volume uses three lengths, a unit change gets cubed. One metre is 100 cm, so one cubic metre is 1003=106100^3 = 10^6 cubic centimetres.

UnitEquals
1 mL1 cm31\ \mathrm{cm^3}
1 L1000 cm31000\ \mathrm{cm^3}
1 m31\ \mathrm{m^3}1000 L, or 1 kilolitre
1 cm31\ \mathrm{cm^3}1000 mm31000\ \mathrm{mm^3}

Example 7: water tank in litres

A cylindrical tank has radius 0.7 m and height 2 m. How many litres does it hold?

V=227×0.7×0.7×2=3.08 m3V = \tfrac{22}{7} \times 0.7 \times 0.7 \times 2 = 3.08\ \mathrm{m^3}.

3.08×1000=30803.08 \times 1000 = 3080 L.

Answer: 3080 litres.

Combination of solids and melting problems

Class 10 loves shapes built from two solids. For the surface area, add only the parts you can see from outside; the joined faces are hidden. For the volume, simply add (or subtract, if one is scooped out).

Example 8: a toy made of a cone on a hemisphere

A toy is a cone of radius 3.5 cm standing on a hemisphere of the same radius. The total height is 15.5 cm. Find its surface area and volume. Take π=227\pi = \tfrac{22}{7}.

Cone height =15.5−3.5=12= 15.5 - 3.5 = 12, slant height =144+12.25=12.5= \sqrt{144 + 12.25} = 12.5.

Surface =2πr2+πrl=77+137.5=214.5 cm2= 2\pi r^2 + \pi rl = 77 + 137.5 = 214.5\ \mathrm{cm^2}.

Volume =23πr3+13πr2h≈89.83+154=243.83 cm3= \tfrac{2}{3}\pi r^3 + \tfrac{1}{3}\pi r^2 h \approx 89.83 + 154 = 243.83\ \mathrm{cm^3}.

Answer: 214.5 cm2214.5\ \mathrm{cm^2} and about 243.83 cm3243.83\ \mathrm{cm^3}.

Example 9: melting and recasting

A metal sphere of radius 6 cm is melted and recast into a cylinder of radius 4 cm. Find the height of the cylinder.

Volume stays the same: π×16×h=43π×216\pi \times 16 \times h = \tfrac{4}{3}\pi \times 216.

π\pi cancels, so 16h=28816h = 288 and h=18h = 18.

Answer: 18 cm.

Surface area and volume formulas for class 9 and class 10

Middle school mensuration starts with the cube, cuboid and cylinder. The class 9 chapter on surface areas and volumes covers the cone, sphere and hemisphere, and class 10 uses these solids in combination problems. Every formula on this page fits on the one-page sheet; print the one-page PDF offered with this page and keep it in your geometry notebook.

The flat-shape formulas these solids rely on, such as the circle, the area of equilateral triangle formula and the area of quadrilateral formula, are on the area formulas page. Base perimeters for prisms come from the perimeter page, and the tools for deriving the sphere formula by calculus are on the integration formulas page.

Download the PDF

Questions students ask

What is the general volume formula?

For any solid with the same cross-section all the way up (cube, cuboid, cylinder, prism), volume is base area times height. For solids that taper to a point (cone, pyramid), it is one third of base area times height.

What is the difference between TSA and CSA?

TSA, total surface area, counts every outer face including the top and bottom. CSA, curved surface area, counts only the curved part (the side of a cylinder or cone, the dome of a hemisphere). For flat-sided solids the same idea is called LSA, lateral surface area.

How many litres are there in one cubic metre?

1000 litres. One litre is 1000 cm31000\ \mathrm{cm^3}, and one cubic metre is 106 cm310^6\ \mathrm{cm^3}.

Why is the volume of a cone one third of a cylinder?

A cone and a cylinder with the same base and height compare in the ratio 1 to 3. You can check it by pouring water, and prove it with integration. The same factor of one third holds for every pyramid.

What is the formula of volume of cube if the diagonal is given?

The space diagonal is 3 a\sqrt{3}\,a, so a=d3a = \tfrac{d}{\sqrt{3}} and V=d333V = \tfrac{d^3}{3\sqrt{3}}. A cube with diagonal 535\sqrt{3} cm has side 5 cm and volume 125 cubic cm.

If the radius of a sphere is doubled, what happens to its volume?

Volume depends on r3r^3, so it becomes 23=82^3 = 8 times as large. The surface area depends on r2r^2, so it becomes 4 times as large.